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Unix User Permalink
October 24, 2008, 00:20

Something I often need to do is match lines against a regexp, and print out a matching group within that line. But I have never been able to find a way to do this in awk, and end up resorting to Perl.

So - is there a way to do something like this?

/abc([0-9]+)def/ { print group(1); }

so that input of:





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