You're replying to a comment by Peter Krumins.

May 16, 2012, 13:40

It's hard to do it in sed.

Here is what $a[$1-1] does. First (\d+) captures the number in the group $1, then $a[$1-1] just accesses the $1-1 element in the @a array.

For example, if the number is 2, then (\d+) captures 2 in $1, and $a[$1-1] is $a[1], which is string "bb", because array @a is ("aa", "bb", "cc", ..., "bx").

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