You're replying to a comment by Peter Krumins.

January 16, 2012, 19:32

It is correct.

Hugs> fmap id [1,2,3]
[1,2,3]
Hugs> id [1,2,3]
[1,2,3]
Hugs> fmap id [1,2,3] == id [1,2,3]
True

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