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alexandru Permalink
July 07, 2009, 12:50

You can always use the O(logN) algorithm to compute nth fibonacci number (or O(NlogN) using your analysis). Your article's point is that big numbers (ie. not implemented in the hardware) don't have constant time operations. :|

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ramsandesh Permalink
April 22, 2010, 02:52

excuse me sir,
I m ram sandesh.I m doing my degree.I m interested in knowing this algorithm with time complexity of O(log n).can u please mail me back graph & algorithm.i guess u have done with matrix multiplication method...

William Permalink
May 26, 2011, 04:08

Actually, the «O(log n)» algorithm is not O(n log n) but O(n^a) where a single call is also O(n^a). If you use naïve long multiplication, a is 2; if you use Karatsuba multiplication, a is log(3)/log(2), which is better.

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