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You can always use the O(logN) algorithm to compute nth fibonacci number (or O(NlogN) using your analysis). Your article's point is that big numbers (ie. not implemented in the hardware) don't have constant time operations. :|
excuse me sir,
I m ram sandesh.I m doing my B.tech degree.I m interested in knowing this algorithm with time complexity of O(log n).can u please mail me back graph & algorithm.i guess u have done with matrix multiplication method...
Actually, the «O(log n)» algorithm is not O(n log n) but O(n^a) where a single call is also O(n^a). If you use naïve long multiplication, a is 2; if you use Karatsuba multiplication, a is log(3)/log(2), which is better.
(why do I need your e-mail?)
It would be nice if you left your e-mail address. Sometimes I want to send a private message, or just thank for the great comment. Having your e-mail really helps.
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