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mave Permalink
November 09, 2008, 03:20

Hi, i saw this question on the other post on Order Statistics, can someone help answer this question

Let X[1::n] and Y [1::n] be two arrays, each containing n numbers already in sorted order.
Give an O(lg n)[in other words an algorithm better than O(n) ] time algorithm to find the nth smallest element of the 2n elements in arrays X and Y, using divide & conquer


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Mahmood Permalink
March 28, 2011, 18:30

did you get the answer?.If yes,tell me because I have interest in your question?
I know It is very late to ask!

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